xref: /llvm-project/llvm/test/Transforms/SCCP/sccptest.ll (revision 10c531cd5bf0166ce5bf42736506733b2285fdf8)
1; NOTE: Assertions have been autogenerated by utils/update_test_checks.py
2; RUN: opt < %s -passes=sccp -S | FileCheck %s
3
4; This is a basic correctness check for constant propagation.  The add
5; instruction should be eliminated.
6
7define i32 @test1(i1 %B) {
8; CHECK-LABEL: @test1(
9; CHECK-NEXT:    br i1 [[B:%.*]], label [[BB1:%.*]], label [[BB2:%.*]]
10; CHECK:       BB1:
11; CHECK-NEXT:    br label [[BB3:%.*]]
12; CHECK:       BB2:
13; CHECK-NEXT:    br label [[BB3]]
14; CHECK:       BB3:
15; CHECK-NEXT:    [[RET:%.*]] = phi i32 [ 0, [[BB1]] ], [ 1, [[BB2]] ]
16; CHECK-NEXT:    ret i32 [[RET]]
17;
18  br i1 %B, label %BB1, label %BB2
19BB1:		; preds = %0
20  %Val = add i32 0, 0		; <i32> [#uses=1]
21  br label %BB3
22BB2:		; preds = %0
23  br label %BB3
24BB3:		; preds = %BB2, %BB1
25  %Ret = phi i32 [ %Val, %BB1 ], [ 1, %BB2 ]		; <i32> [#uses=1]
26  ret i32 %Ret
27
28}
29
30; This is the test case taken from appel's book that illustrates a hard case
31; that SCCP gets right.
32;
33define i32 @test2(i32 %i0, i32 %j0) {
34; CHECK-LABEL: @test2(
35; CHECK-NEXT:  BB1:
36; CHECK-NEXT:    br label [[BB2:%.*]]
37; CHECK:       BB2:
38; CHECK-NEXT:    [[K2:%.*]] = phi i32 [ [[K3:%.*]], [[BB7:%.*]] ], [ 0, [[BB1:%.*]] ]
39; CHECK-NEXT:    [[KCOND:%.*]] = icmp slt i32 [[K2]], 100
40; CHECK-NEXT:    br i1 [[KCOND]], label [[BB3:%.*]], label [[BB4:%.*]]
41; CHECK:       BB3:
42; CHECK-NEXT:    br label [[BB5:%.*]]
43; CHECK:       BB4:
44; CHECK-NEXT:    ret i32 1
45; CHECK:       BB5:
46; CHECK-NEXT:    [[K3]] = add i32 [[K2]], 1
47; CHECK-NEXT:    br label [[BB7]]
48; CHECK:       BB7:
49; CHECK-NEXT:    br label [[BB2]]
50;
51BB1:
52  br label %BB2
53BB2:
54  %j2 = phi i32 [ %j4, %BB7 ], [ 1, %BB1 ]
55  %k2 = phi i32 [ %k4, %BB7 ], [ 0, %BB1 ]
56  %kcond = icmp slt i32 %k2, 100
57  br i1 %kcond, label %BB3, label %BB4
58BB3:
59  %jcond = icmp slt i32 %j2, 20
60  br i1 %jcond, label %BB5, label %BB6
61BB4:
62  ret i32 %j2
63BB5:
64  %k3 = add i32 %k2, 1
65  br label %BB7
66BB6:
67  %k5 = add i32 %k2, 1
68  br label %BB7
69BB7:
70  %j4 = phi i32 [ 1, %BB5 ], [ %k2, %BB6 ]
71  %k4 = phi i32 [ %k3, %BB5 ], [ %k5, %BB6 ]
72  br label %BB2
73}
74
75