1 // RUN: %clang_analyze_cc1 %s \ 2 // RUN: -analyzer-checker=core \ 3 // RUN: -analyzer-checker=debug.ExprInspection \ 4 // RUN: 2>&1 | FileCheck %s 5 6 // In this test we check whether the solver's symbol simplification mechanism 7 // is capable of reaching a fixpoint. This should be done after one iteration. 8 9 void clang_analyzer_printState(); 10 11 void test(int a, int b, int c) { 12 if (a + b != c) 13 return; 14 clang_analyzer_printState(); 15 // CHECK: "constraints": [ 16 // CHECK-NEXT: { "symbol": "((reg_$0<int a>) + (reg_$2<int b>)) != (reg_$5<int c>)", "range": "{ [0, 0] }" } 17 // CHECK-NEXT: ], 18 // CHECK-NEXT: "equivalence_classes": [ 19 // CHECK-NEXT: [ "(reg_$0<int a>) + (reg_$2<int b>)", "reg_$5<int c>" ] 20 // CHECK-NEXT: ], 21 // CHECK-NEXT: "disequality_info": null, 22 23 // Simplification starts here. 24 if (b != 0) 25 return; 26 clang_analyzer_printState(); 27 // CHECK: "constraints": [ 28 // CHECK-NEXT: { "symbol": "(reg_$0<int a>) != (reg_$5<int c>)", "range": "{ [0, 0] }" }, 29 // CHECK-NEXT: { "symbol": "reg_$2<int b>", "range": "{ [0, 0] }" } 30 // CHECK-NEXT: ], 31 // CHECK-NEXT: "equivalence_classes": [ 32 // CHECK-NEXT: [ "(reg_$0<int a>) != (reg_$5<int c>)" ], 33 // CHECK-NEXT: [ "reg_$0<int a>", "reg_$5<int c>" ] 34 // CHECK-NEXT: ], 35 // CHECK-NEXT: "disequality_info": null, 36 37 // Keep the symbols and the constraints! alive. 38 (void)(a * b * c); 39 return; 40 } 41