xref: /openbsd-src/usr.sbin/dhcpd/tree.c (revision b725ae7711052a2233e31a66fefb8a752c388d7a)
1 /*	$OpenBSD: tree.c,v 1.9 2004/05/08 06:12:50 henning Exp $ */
2 
3 /* Routines for manipulating parse trees... */
4 
5 /*
6  * Copyright (c) 1995, 1996, 1997 The Internet Software Consortium.
7  * All rights reserved.
8  *
9  * Redistribution and use in source and binary forms, with or without
10  * modification, are permitted provided that the following conditions
11  * are met:
12  *
13  * 1. Redistributions of source code must retain the above copyright
14  *    notice, this list of conditions and the following disclaimer.
15  * 2. Redistributions in binary form must reproduce the above copyright
16  *    notice, this list of conditions and the following disclaimer in the
17  *    documentation and/or other materials provided with the distribution.
18  * 3. Neither the name of The Internet Software Consortium nor the names
19  *    of its contributors may be used to endorse or promote products derived
20  *    from this software without specific prior written permission.
21  *
22  * THIS SOFTWARE IS PROVIDED BY THE INTERNET SOFTWARE CONSORTIUM AND
23  * CONTRIBUTORS ``AS IS'' AND ANY EXPRESS OR IMPLIED WARRANTIES,
24  * INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES OF
25  * MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE
26  * DISCLAIMED.  IN NO EVENT SHALL THE INTERNET SOFTWARE CONSORTIUM OR
27  * CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
28  * SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
29  * LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF
30  * USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND
31  * ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY,
32  * OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT
33  * OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF
34  * SUCH DAMAGE.
35  *
36  * This software has been written for the Internet Software Consortium
37  * by Ted Lemon <mellon@fugue.com> in cooperation with Vixie
38  * Enterprises.  To learn more about the Internet Software Consortium,
39  * see ``http://www.vix.com/isc''.  To learn more about Vixie
40  * Enterprises, see ``http://www.vix.com''.
41  */
42 
43 #include "dhcpd.h"
44 
45 static time_t tree_evaluate_recurse(int *, unsigned char **, int *,
46     struct tree *);
47 static void do_data_copy(int *, unsigned char **, int *, unsigned char *, int);
48 
49 pair
50 cons(caddr_t car, pair cdr)
51 {
52 	pair	foo = (pair)dmalloc(sizeof *foo, "cons");
53 	if (!foo)
54 		error("no memory for cons.");
55 	foo->car = car;
56 	foo->cdr = cdr;
57 	return foo;
58 }
59 
60 struct tree_cache *
61 tree_cache(struct tree *tree)
62 {
63 	struct tree_cache	*tc;
64 
65 	tc = new_tree_cache("tree_cache");
66 	if (!tc)
67 		return 0;
68 	tc->value = NULL;
69 	tc->len = tc->buf_size = 0;
70 	tc->timeout = 0;
71 	tc->tree = tree;
72 	return tc;
73 }
74 
75 struct tree *
76 tree_host_lookup(char *name)
77 {
78 	struct tree	*nt;
79 
80 	nt = new_tree("tree_host_lookup");
81 	if (!nt)
82 		error("No memory for host lookup tree node.");
83 	nt->op = TREE_HOST_LOOKUP;
84 	nt->data.host_lookup.host = enter_dns_host(name);
85 	return nt;
86 }
87 
88 struct dns_host_entry *
89 enter_dns_host(char *name)
90 {
91 	struct dns_host_entry	*dh;
92 	int			 len = strlen(name) + 1;
93 
94 	if (!(dh = (struct dns_host_entry *)dmalloc
95 	    (sizeof(struct dns_host_entry), "enter_dns_host")) ||
96 	    !(dh->hostname = dmalloc(len, "enter_dns_host")))
97 		error("Can't allocate space for new host.");
98 	strlcpy(dh->hostname, name, len);
99 	dh->data = NULL;
100 	dh->data_len = 0;
101 	dh->buf_len = 0;
102 	dh->timeout = 0;
103 	return dh;
104 }
105 
106 struct tree *
107 tree_const(unsigned char *data, int len)
108 {
109 	struct tree	*nt;
110 
111 	if (!(nt = new_tree("tree_const")) || !(nt->data.const_val.data =
112 	    (unsigned char *)dmalloc(len, "tree_const")))
113 		error("No memory for constant data tree node.");
114 	nt->op = TREE_CONST;
115 	memcpy(nt->data.const_val.data, data, len);
116 	nt->data.const_val.len = len;
117 	return nt;
118 }
119 
120 struct tree *
121 tree_concat(struct tree *left, struct tree *right)
122 {
123 	struct tree	*nt;
124 
125 	/*
126 	 * If we're concatenating a null tree to a non-null tree, just
127 	 * return the non-null tree; if both trees are null, return
128 	 * a null tree.
129 	 */
130 	if (!left)
131 		return right;
132 	if (!right)
133 		return left;
134 
135 	/* If both trees are constant, combine them. */
136 	if (left->op == TREE_CONST && right->op == TREE_CONST) {
137 		unsigned char *buf = dmalloc(left->data.const_val.len
138 		    + right->data.const_val.len, "tree_concat");
139 
140 		if (!buf)
141 			error("No memory to concatenate constants.");
142 		memcpy(buf, left->data.const_val.data,
143 		    left->data.const_val.len);
144 		memcpy(buf + left->data.const_val.len,
145 		    right->data.const_val.data, right->data.const_val.len);
146 		dfree(left->data.const_val.data, "tree_concat");
147 		dfree(right->data.const_val.data, "tree_concat");
148 		left->data.const_val.data = buf;
149 		left->data.const_val.len += right->data.const_val.len;
150 		free_tree(right, "tree_concat");
151 		return left;
152 	}
153 
154 	/* Otherwise, allocate a new node to concatenate the two. */
155 	if (!(nt = new_tree("tree_concat")))
156 		error("No memory for data tree concatenation node.");
157 	nt->op = TREE_CONCAT;
158 	nt->data.concat.left = left;
159 	nt->data.concat.right = right;
160 	return nt;
161 }
162 
163 struct tree *
164 tree_limit(struct tree *tree, int limit)
165 {
166 	struct tree	*rv;
167 
168 	/* If the tree we're limiting is constant, limit it now. */
169 	if (tree->op == TREE_CONST) {
170 		if (tree->data.const_val.len > limit)
171 			tree->data.const_val.len = limit;
172 		return tree;
173 	}
174 
175 	/* Otherwise, put in a node which enforces the limit on evaluation. */
176 	rv = new_tree("tree_limit");
177 	if (!rv)
178 		return NULL;
179 	rv->op = TREE_LIMIT;
180 	rv->data.limit.tree = tree;
181 	rv->data.limit.limit = limit;
182 	return rv;
183 }
184 
185 int
186 tree_evaluate(struct tree_cache *tree_cache)
187 {
188 	unsigned char	*bp = tree_cache->value;
189 	int		 bc = tree_cache->buf_size;
190 	int		 bufix = 0;
191 
192 	/*
193 	 * If there's no tree associated with this cache, it evaluates to a
194 	 * constant and that was detected at startup.
195 	 */
196 	if (!tree_cache->tree)
197 		return 1;
198 
199 	/* Try to evaluate the tree without allocating more memory... */
200 	tree_cache->timeout = tree_evaluate_recurse(&bufix, &bp, &bc,
201 	    tree_cache->tree);
202 
203 	/* No additional allocation needed? */
204 	if (bufix <= bc) {
205 		tree_cache->len = bufix;
206 		return 1;
207 	}
208 
209 	/*
210 	 * If we can't allocate more memory, return with what we
211 	 * have (maybe nothing).
212 	 */
213 	if (!(bp = (unsigned char *)dmalloc(bufix, "tree_evaluate")))
214 		return 0;
215 
216 	/* Record the change in conditions... */
217 	bc = bufix;
218 	bufix = 0;
219 
220 	/*
221 	 * Note that the size of the result shouldn't change on the
222 	 * second call to tree_evaluate_recurse, since we haven't
223 	 * changed the ``current'' time.
224 	 */
225 	tree_evaluate_recurse(&bufix, &bp, &bc, tree_cache->tree);
226 
227 	/*
228 	 * Free the old buffer if needed, then store the new buffer
229 	 * location and size and return.
230 	 */
231 	if (tree_cache->value)
232 		dfree(tree_cache->value, "tree_evaluate");
233 	tree_cache->value = bp;
234 	tree_cache->len = bufix;
235 	tree_cache->buf_size = bc;
236 	return 1;
237 }
238 
239 static time_t
240 tree_evaluate_recurse(int *bufix, unsigned char **bufp,
241     int *bufcount, struct tree *tree)
242 {
243 	int	limit;
244 	time_t	t1, t2;
245 
246 	switch (tree->op) {
247 	case TREE_CONCAT:
248 		t1 = tree_evaluate_recurse(bufix, bufp, bufcount,
249 		    tree->data.concat.left);
250 		t2 = tree_evaluate_recurse(bufix, bufp, bufcount,
251 		    tree->data.concat.right);
252 		if (t1 > t2)
253 			return t2;
254 		return t1;
255 
256 	case TREE_CONST:
257 		do_data_copy(bufix, bufp, bufcount, tree->data.const_val.data,
258 		    tree->data.const_val.len);
259 		t1 = MAX_TIME;
260 		return t1;
261 
262 	case TREE_LIMIT:
263 		limit = *bufix + tree->data.limit.limit;
264 		t1 = tree_evaluate_recurse(bufix, bufp, bufcount,
265 		    tree->data.limit.tree);
266 		*bufix = limit;
267 		return t1;
268 
269 	default:
270 		warn("Bad node id in tree: %d.", tree->op);
271 		t1 = MAX_TIME;
272 		return t1;
273 	}
274 }
275 
276 static void
277 do_data_copy(int *bufix, unsigned char **bufp, int *bufcount,
278     unsigned char *data, int len)
279 {
280 	int	space = *bufcount - *bufix;
281 
282 	/* If there's more space than we need, use only what we need. */
283 	if (space > len)
284 		space = len;
285 
286 	/*
287 	 * Copy as much data as will fit, then increment the buffer index
288 	 * by the amount we actually had to copy, which could be more.
289 	 */
290 	if (space > 0)
291 		memcpy(*bufp + *bufix, data, space);
292 	*bufix += len;
293 }
294