1 /* $NetBSD: str.c,v 1.26 2006/12/22 20:28:31 erh Exp $ */ 2 3 /*- 4 * Copyright (c) 1988, 1989, 1990, 1993 5 * The Regents of the University of California. All rights reserved. 6 * 7 * This code is derived from software contributed to Berkeley by 8 * Adam de Boor. 9 * 10 * Redistribution and use in source and binary forms, with or without 11 * modification, are permitted provided that the following conditions 12 * are met: 13 * 1. Redistributions of source code must retain the above copyright 14 * notice, this list of conditions and the following disclaimer. 15 * 2. Redistributions in binary form must reproduce the above copyright 16 * notice, this list of conditions and the following disclaimer in the 17 * documentation and/or other materials provided with the distribution. 18 * 3. Neither the name of the University nor the names of its contributors 19 * may be used to endorse or promote products derived from this software 20 * without specific prior written permission. 21 * 22 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND 23 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE 24 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE 25 * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE 26 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL 27 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS 28 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) 29 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT 30 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY 31 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF 32 * SUCH DAMAGE. 33 */ 34 35 /*- 36 * Copyright (c) 1989 by Berkeley Softworks 37 * All rights reserved. 38 * 39 * This code is derived from software contributed to Berkeley by 40 * Adam de Boor. 41 * 42 * Redistribution and use in source and binary forms, with or without 43 * modification, are permitted provided that the following conditions 44 * are met: 45 * 1. Redistributions of source code must retain the above copyright 46 * notice, this list of conditions and the following disclaimer. 47 * 2. Redistributions in binary form must reproduce the above copyright 48 * notice, this list of conditions and the following disclaimer in the 49 * documentation and/or other materials provided with the distribution. 50 * 3. All advertising materials mentioning features or use of this software 51 * must display the following acknowledgement: 52 * This product includes software developed by the University of 53 * California, Berkeley and its contributors. 54 * 4. Neither the name of the University nor the names of its contributors 55 * may be used to endorse or promote products derived from this software 56 * without specific prior written permission. 57 * 58 * THIS SOFTWARE IS PROVIDED BY THE REGENTS AND CONTRIBUTORS ``AS IS'' AND 59 * ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE 60 * IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE 61 * ARE DISCLAIMED. IN NO EVENT SHALL THE REGENTS OR CONTRIBUTORS BE LIABLE 62 * FOR ANY DIRECT, INDIRECT, INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL 63 * DAMAGES (INCLUDING, BUT NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS 64 * OR SERVICES; LOSS OF USE, DATA, OR PROFITS; OR BUSINESS INTERRUPTION) 65 * HOWEVER CAUSED AND ON ANY THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT 66 * LIABILITY, OR TORT (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY 67 * OUT OF THE USE OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF 68 * SUCH DAMAGE. 69 */ 70 71 #ifndef MAKE_NATIVE 72 static char rcsid[] = "$NetBSD: str.c,v 1.26 2006/12/22 20:28:31 erh Exp $"; 73 #else 74 #include <sys/cdefs.h> 75 #ifndef lint 76 #if 0 77 static char sccsid[] = "@(#)str.c 5.8 (Berkeley) 6/1/90"; 78 #else 79 __RCSID("$NetBSD: str.c,v 1.26 2006/12/22 20:28:31 erh Exp $"); 80 #endif 81 #endif /* not lint */ 82 #endif 83 84 #include "make.h" 85 86 /*- 87 * str_concat -- 88 * concatenate the two strings, inserting a space or slash between them, 89 * freeing them if requested. 90 * 91 * returns -- 92 * the resulting string in allocated space. 93 */ 94 char * 95 str_concat(const char *s1, const char *s2, int flags) 96 { 97 int len1, len2; 98 char *result; 99 100 /* get the length of both strings */ 101 len1 = strlen(s1); 102 len2 = strlen(s2); 103 104 /* allocate length plus separator plus EOS */ 105 result = emalloc((u_int)(len1 + len2 + 2)); 106 107 /* copy first string into place */ 108 memcpy(result, s1, len1); 109 110 /* add separator character */ 111 if (flags & STR_ADDSPACE) { 112 result[len1] = ' '; 113 ++len1; 114 } else if (flags & STR_ADDSLASH) { 115 result[len1] = '/'; 116 ++len1; 117 } 118 119 /* copy second string plus EOS into place */ 120 memcpy(result + len1, s2, len2 + 1); 121 122 return(result); 123 } 124 125 /*- 126 * brk_string -- 127 * Fracture a string into an array of words (as delineated by tabs or 128 * spaces) taking quotation marks into account. Leading tabs/spaces 129 * are ignored. 130 * 131 * If expand is TRUE, quotes are removed and escape sequences 132 * such as \r, \t, etc... are expanded. 133 * 134 * returns -- 135 * Pointer to the array of pointers to the words. 136 * Memory containing the actual words in *buffer. 137 * Both of these must be free'd by the caller. 138 * Number of words in *store_argc. 139 */ 140 char ** 141 brk_string(const char *str, int *store_argc, Boolean expand, char **buffer) 142 { 143 int argc, ch; 144 char inquote, *start, *t; 145 const char *p; 146 int len; 147 int argmax = 50, curlen = 0; 148 char **argv = emalloc((argmax + 1) * sizeof(char *)); 149 150 /* skip leading space chars. */ 151 for (; *str == ' ' || *str == '\t'; ++str) 152 continue; 153 154 /* allocate room for a copy of the string */ 155 if ((len = strlen(str) + 1) > curlen) 156 *buffer = emalloc(curlen = len); 157 158 /* 159 * copy the string; at the same time, parse backslashes, 160 * quotes and build the argument list. 161 */ 162 argc = 0; 163 inquote = '\0'; 164 for (p = str, start = t = *buffer;; ++p) { 165 switch(ch = *p) { 166 case '"': 167 case '\'': 168 if (inquote) { 169 if (inquote == ch) 170 inquote = '\0'; 171 else 172 break; 173 } 174 else { 175 inquote = (char) ch; 176 /* Don't miss "" or '' */ 177 if (start == NULL && p[1] == inquote) { 178 start = t + 1; 179 p++; 180 inquote = '\0'; 181 break; 182 } 183 } 184 if (!expand) { 185 if (!start) 186 start = t; 187 *t++ = ch; 188 } 189 continue; 190 case ' ': 191 case '\t': 192 case '\n': 193 if (inquote) 194 break; 195 if (!start) 196 continue; 197 /* FALLTHROUGH */ 198 case '\0': 199 /* 200 * end of a token -- make sure there's enough argv 201 * space and save off a pointer. 202 */ 203 if (!start) 204 goto done; 205 206 *t++ = '\0'; 207 if (argc == argmax) { 208 argmax *= 2; /* ramp up fast */ 209 argv = (char **)erealloc(argv, 210 (argmax + 1) * sizeof(char *)); 211 } 212 argv[argc++] = start; 213 start = NULL; 214 if (ch == '\n' || ch == '\0') 215 goto done; 216 continue; 217 case '\\': 218 if (!expand) { 219 if (!start) 220 start = t; 221 *t++ = '\\'; 222 if (*(p+1) == '\0') // catch '\' at end of line 223 continue; 224 ch = *++p; 225 break; 226 } 227 228 switch (ch = *++p) { 229 case '\0': 230 case '\n': 231 /* hmmm; fix it up as best we can */ 232 ch = '\\'; 233 --p; 234 break; 235 case 'b': 236 ch = '\b'; 237 break; 238 case 'f': 239 ch = '\f'; 240 break; 241 case 'n': 242 ch = '\n'; 243 break; 244 case 'r': 245 ch = '\r'; 246 break; 247 case 't': 248 ch = '\t'; 249 break; 250 } 251 break; 252 } 253 if (!start) 254 start = t; 255 *t++ = (char) ch; 256 } 257 done: argv[argc] = NULL; 258 *store_argc = argc; 259 return(argv); 260 } 261 262 /* 263 * Str_FindSubstring -- See if a string contains a particular substring. 264 * 265 * Input: 266 * string String to search. 267 * substring Substring to find in string. 268 * 269 * Results: If string contains substring, the return value is the location of 270 * the first matching instance of substring in string. If string doesn't 271 * contain substring, the return value is NULL. Matching is done on an exact 272 * character-for-character basis with no wildcards or special characters. 273 * 274 * Side effects: None. 275 */ 276 char * 277 Str_FindSubstring(const char *string, const char *substring) 278 { 279 const char *a, *b; 280 281 /* 282 * First scan quickly through the two strings looking for a single- 283 * character match. When it's found, then compare the rest of the 284 * substring. 285 */ 286 287 for (b = substring; *string != 0; string += 1) { 288 if (*string != *b) 289 continue; 290 a = string; 291 for (;;) { 292 if (*b == 0) 293 return UNCONST(string); 294 if (*a++ != *b++) 295 break; 296 } 297 b = substring; 298 } 299 return NULL; 300 } 301 302 /* 303 * Str_Match -- 304 * 305 * See if a particular string matches a particular pattern. 306 * 307 * Results: Non-zero is returned if string matches pattern, 0 otherwise. The 308 * matching operation permits the following special characters in the 309 * pattern: *?\[] (see the man page for details on what these mean). 310 * 311 * Side effects: None. 312 */ 313 int 314 Str_Match(const char *string, const char *pattern) 315 { 316 char c2; 317 318 for (;;) { 319 /* 320 * See if we're at the end of both the pattern and the 321 * string. If, we succeeded. If we're at the end of the 322 * pattern but not at the end of the string, we failed. 323 */ 324 if (*pattern == 0) 325 return(!*string); 326 if (*string == 0 && *pattern != '*') 327 return(0); 328 /* 329 * Check for a "*" as the next pattern character. It matches 330 * any substring. We handle this by calling ourselves 331 * recursively for each postfix of string, until either we 332 * match or we reach the end of the string. 333 */ 334 if (*pattern == '*') { 335 pattern += 1; 336 if (*pattern == 0) 337 return(1); 338 while (*string != 0) { 339 if (Str_Match(string, pattern)) 340 return(1); 341 ++string; 342 } 343 return(0); 344 } 345 /* 346 * Check for a "?" as the next pattern character. It matches 347 * any single character. 348 */ 349 if (*pattern == '?') 350 goto thisCharOK; 351 /* 352 * Check for a "[" as the next pattern character. It is 353 * followed by a list of characters that are acceptable, or 354 * by a range (two characters separated by "-"). 355 */ 356 if (*pattern == '[') { 357 ++pattern; 358 for (;;) { 359 if ((*pattern == ']') || (*pattern == 0)) 360 return(0); 361 if (*pattern == *string) 362 break; 363 if (pattern[1] == '-') { 364 c2 = pattern[2]; 365 if (c2 == 0) 366 return(0); 367 if ((*pattern <= *string) && 368 (c2 >= *string)) 369 break; 370 if ((*pattern >= *string) && 371 (c2 <= *string)) 372 break; 373 pattern += 2; 374 } 375 ++pattern; 376 } 377 while ((*pattern != ']') && (*pattern != 0)) 378 ++pattern; 379 goto thisCharOK; 380 } 381 /* 382 * If the next pattern character is '/', just strip off the 383 * '/' so we do exact matching on the character that follows. 384 */ 385 if (*pattern == '\\') { 386 ++pattern; 387 if (*pattern == 0) 388 return(0); 389 } 390 /* 391 * There's no special character. Just make sure that the 392 * next characters of each string match. 393 */ 394 if (*pattern != *string) 395 return(0); 396 thisCharOK: ++pattern; 397 ++string; 398 } 399 } 400 401 402 /*- 403 *----------------------------------------------------------------------- 404 * Str_SYSVMatch -- 405 * Check word against pattern for a match (% is wild), 406 * 407 * Input: 408 * word Word to examine 409 * pattern Pattern to examine against 410 * len Number of characters to substitute 411 * 412 * Results: 413 * Returns the beginning position of a match or null. The number 414 * of characters matched is returned in len. 415 * 416 * Side Effects: 417 * None 418 * 419 *----------------------------------------------------------------------- 420 */ 421 char * 422 Str_SYSVMatch(const char *word, const char *pattern, int *len) 423 { 424 const char *p = pattern; 425 const char *w = word; 426 const char *m; 427 428 if (*p == '\0') { 429 /* Null pattern is the whole string */ 430 *len = strlen(w); 431 return UNCONST(w); 432 } 433 434 if ((m = strchr(p, '%')) != NULL) { 435 /* check that the prefix matches */ 436 for (; p != m && *w && *w == *p; w++, p++) 437 continue; 438 439 if (p != m) 440 return NULL; /* No match */ 441 442 if (*++p == '\0') { 443 /* No more pattern, return the rest of the string */ 444 *len = strlen(w); 445 return UNCONST(w); 446 } 447 } 448 449 m = w; 450 451 /* Find a matching tail */ 452 do 453 if (strcmp(p, w) == 0) { 454 *len = w - m; 455 return UNCONST(m); 456 } 457 while (*w++ != '\0'); 458 459 return NULL; 460 } 461 462 463 /*- 464 *----------------------------------------------------------------------- 465 * Str_SYSVSubst -- 466 * Substitute '%' on the pattern with len characters from src. 467 * If the pattern does not contain a '%' prepend len characters 468 * from src. 469 * 470 * Results: 471 * None 472 * 473 * Side Effects: 474 * Places result on buf 475 * 476 *----------------------------------------------------------------------- 477 */ 478 void 479 Str_SYSVSubst(Buffer buf, char *pat, char *src, int len) 480 { 481 char *m; 482 483 if ((m = strchr(pat, '%')) != NULL) { 484 /* Copy the prefix */ 485 Buf_AddBytes(buf, m - pat, (Byte *)pat); 486 /* skip the % */ 487 pat = m + 1; 488 } 489 490 /* Copy the pattern */ 491 Buf_AddBytes(buf, len, (Byte *)src); 492 493 /* append the rest */ 494 Buf_AddBytes(buf, strlen(pat), (Byte *)pat); 495 } 496