xref: /netbsd-src/tests/usr.bin/xlint/lint1/expr_precedence.c (revision b0d1725196a7921d003d2c66a14f186abda4176b)
1 /*	$NetBSD: expr_precedence.c,v 1.11 2023/03/28 14:44:34 rillig Exp $	*/
2 # 3 "expr_precedence.c"
3 
4 /*
5  * Tests for the precedence among operators.
6  */
7 
8 /* lint1-extra-flags: -X 351 */
9 
10 int var;
11 
12 /*
13  * An initializer needs an assignment-expression; the comma must be
14  * interpreted as a separator, not an operator.
15  */
16 /* expect+1: error: syntax error '4' [249] */
17 int init_error = 3, 4;
18 
19 /* expect+1: error: non-constant initializer [177] */
20 int init_syntactically_ok = var = 1 ? 2 : 3;
21 
22 /*
23  * The arguments of __attribute__ must be constant-expression, as assignments
24  * don't make sense at that point.
25  */
26 void __attribute__((format(printf,
27     /*
28      * Inside of __attribute__((...)), symbol lookup works differently.  For
29      * example, 'printf' is a keyword, and since all arguments to
30      * __attribute__ are constant expressions, looking up global variables
31      * would not make sense.  Therefore, 'var' is undefined.
32      *
33      * See lex.c, function 'search', keyword 'in_gcc_attribute'.
34      */
35     /* expect+1: error: syntax error '=' [249] */
36     var = 1,
37     /* Syntactically ok, must be a constant expression though. */
38     var > 0 ? 2 : 1)))
39 my_printf(const char *, ...);
40 
41 void
42 assignment_associativity(int arg)
43 {
44 	int left, right;
45 
46 	/*
47 	 * Assignments are right-associative.  If they were left-associative,
48 	 * the result of (left = right) would be an rvalue, resulting in this
49 	 * error message: 'left operand of '=' must be lvalue [114]'.
50 	 */
51 	left = right = arg;
52 
53 	left = arg;
54 }
55 
56 void
57 conditional_associativity(_Bool cond1, _Bool cond2, int a, int b, int c)
58 {
59 	/* The then-expression can be an arbitrary expression. */
60 	var = cond1 ? cond2 ? a : b : c;
61 	var = cond1 ? (cond2 ? a : b) : c;
62 
63 	/* The then-expression can even be a comma-expression. */
64 	var = cond1 ? cond2 ? a, b : (b, a) : c;
65 
66 	var = cond1 ? a : cond2 ? b : c;
67 	/*
68 	 * In almost all programming languages, '?:' is right-associative,
69 	 * which allows for easy chaining.
70 	 */
71 	var = cond1 ? a : (cond2 ? b : c);
72 	/*
73 	 * In PHP, '?:' is left-associative, which is rather surprising and
74 	 * requires more parentheses to get the desired effect.
75 	 */
76 	var = (cond1 ? a : cond2) ? b : c;
77 }
78