xref: /netbsd-src/tests/usr.bin/xlint/lint1/expr_precedence.c (revision a649f3d0e923af16d0c7d20a55e676735e97827c)
1 /*	$NetBSD: expr_precedence.c,v 1.10 2022/08/25 19:03:48 rillig Exp $	*/
2 # 3 "expr_precedence.c"
3 
4 /*
5  * Tests for the precedence among operators.
6  */
7 
8 int var;
9 
10 /*
11  * An initializer needs an assignment-expression; the comma must be
12  * interpreted as a separator, not an operator.
13  */
14 /* expect+1: error: syntax error '4' [249] */
15 int init_error = 3, 4;
16 
17 /* expect+1: error: non-constant initializer [177] */
18 int init_syntactically_ok = var = 1 ? 2 : 3;
19 
20 /*
21  * The arguments of __attribute__ must be constant-expression, as assignments
22  * don't make sense at that point.
23  */
24 void __attribute__((format(printf,
25     /*
26      * Inside of __attribute__((...)), symbol lookup works differently.  For
27      * example, 'printf' is a keyword, and since all arguments to
28      * __attribute__ are constant expressions, looking up global variables
29      * would not make sense.  Therefore, 'var' is undefined.
30      *
31      * See lex.c, function 'search', keyword 'in_gcc_attribute'.
32      */
33     /* expect+1: error: syntax error '=' [249] */
34     var = 1,
35     /* Syntactically ok, must be a constant expression though. */
36     var > 0 ? 2 : 1)))
37 my_printf(const char *, ...);
38 
39 void
40 assignment_associativity(int arg)
41 {
42 	int left, right;
43 
44 	/*
45 	 * Assignments are right-associative.  If they were left-associative,
46 	 * the result of (left = right) would be an rvalue, resulting in this
47 	 * error message: 'left operand of '=' must be lvalue [114]'.
48 	 */
49 	left = right = arg;
50 
51 	left = arg;
52 }
53 
54 void
55 conditional_associativity(_Bool cond1, _Bool cond2, int a, int b, int c)
56 {
57 	/* The then-expression can be an arbitrary expression. */
58 	var = cond1 ? cond2 ? a : b : c;
59 	var = cond1 ? (cond2 ? a : b) : c;
60 
61 	/* The then-expression can even be a comma-expression. */
62 	var = cond1 ? cond2 ? a, b : (b, a) : c;
63 
64 	var = cond1 ? a : cond2 ? b : c;
65 	/*
66 	 * In almost all programming languages, '?:' is right-associative,
67 	 * which allows for easy chaining.
68 	 */
69 	var = cond1 ? a : (cond2 ? b : c);
70 	/*
71 	 * In PHP, '?:' is left-associative, which is rather surprising and
72 	 * requires more parentheses to get the desired effect.
73 	 */
74 	var = (cond1 ? a : cond2) ? b : c;
75 }
76