Searched refs:min_multiple (Results 1 – 1 of 1) sorted by relevance
3031 int last_conflict, min_multiple; in analyze_subscript_affine_affine() local3042 min_multiple = MIN (x0 / i1, y0 / j1); in analyze_subscript_affine_affine()3043 x0 -= i1 * min_multiple; in analyze_subscript_affine_affine()3044 y0 -= j1 * min_multiple; in analyze_subscript_affine_affine()