Searched refs:prev_time (Results 1 – 1 of 1) sorted by relevance
572 double prev_time; member675 if (choice[i].prev_time == -1.0) in run_one()678 choice[i].time = choice[i].time - choice[i].prev_time; in run_one()680 choice[i].prev_time = t; in run_one()