Searched refs:kPdbgRegex (Results 1 – 1 of 1) sorted by relevance
50 kPdbgRegex = '%dbg\\(([^)\'"]*)\\)' variable899 ln = commands[i] = re.sub(kPdbgRegex, ": '\\1'; ", ln)987 commands[i] = re.sub(kPdbgRegex, "echo '\\1' > nul && ", ln)995 commands[i] = re.sub(kPdbgRegex, ": '\\1'; ", ln)1361 assert re.match(kPdbgRegex + "$", pdbg), \