Searched refs:e_char (Results 1 – 5 of 5) sorted by relevance
470 for (p = etable; p->e_char; p++) in escape()471 if (p->e_char == gch) { in escape()545 for (p = etable; p->e_char; p++) { in help()549 (void)printf("%-2s %c %s\r\n", ctrl(p->e_char), in help()
60 { .e_char = '\0' }
171 char e_char; /* char to match on */ member
65 ep->e_char = type; in showexpl()128 if (pp->p_maze[y][x] == ep->e_char) { in rollexpl()
124 char e_char; member