Searched refs:LItr (Results 1 – 1 of 1) sorted by relevance
143 iterator LItr = begin(), LEnd = end(); in isEqual() local146 while (LItr != LEnd && RItr != REnd) { in isEqual()147 if (&*LItr == &*RItr) { in isEqual()148 LItr.skipSubTree(); in isEqual()153 if (!LItr->isElementEqual(&*RItr)) in isEqual()156 ++LItr; in isEqual()160 return LItr == LEnd && RItr == REnd; in isEqual()