Searched refs:blarg (Results 1 – 20 of 20) sorted by relevance
21 int blarg = 0; in f1() local23 blarg = blarg + x * i; in f1()24 return blarg; in f1()
37 using namespace ::blarg; // expected-error{{no namespace named 'blarg' in the global namespace; did…39 namespace wibble = blarg; // expected-error{{no namespace named 'blarg'; did you mean 'blargh'?}}40 namespace wobble = ::blarg; // expected-error{{no namespace named 'blarg' in the global namespace; …
9 void blarg(int, ...); // expected-note {{previous}}10 void blarg() {} // expected-error {{conflicting types for 'blarg'}} in blarg() function
35 virtual void blarg();38 template<typename T> void X1<T>::blarg() { } in blarg() function in X1
47 6: FOO(blarg)52 7: FOO(blarg)
48 import x [[blarg::noreturn]]; // expected-warning {{unknown attribute 'noreturn' ignored}}54 import blarg; // expected-error {{module 'blarg' not found}}
8 #warning blarg9 #error blarg
19 @property (getter = getter4, setter = setter1:) int blarg; property
10 blarg * blah = wibble;
121 [[x blarg] Method:1 Arg1:1 OtherArg:ovl];
121 - (int)blarg:(int)x {
132 + (X1<float>&)blarg; class137 [B blarg];
21 A* blarg(double *dp) { in blarg() function
10 @"baz" " blarg";
38 declare fastcc void @blarg() nounwind uwtable readonly67 tail call fastcc void @blarg()161 tail call fastcc void @blarg()281 tail call fastcc void @blarg()
66 - Name: .blarg
389 typedef bool (__stdcall __stdcall *blarg)(int);
24 blarg
1956 This example forms a string like "blarg.42" by concatenating the values1957 together, and does not form intermediate strings containing "blarg" or "blarg.".